1. **State the problem:** Find the Highest Common Factor (HCF) of 112, 224, and 336. 2. **Formula and rules:** The HCF of numbers is the largest number that divides all of them without leaving a remainder. One way to find it is by prime factorization or using the Euclidean algorithm. 3. **Prime factorization:** - 112 = $2^4 \times 7$ - 224 = $2^5 \times 7$ - 336 = $2^4 \times 3 \times 7$ 4. **Find common prime factors with smallest powers:** - Common prime factors are 2 and 7. - Smallest power of 2 among the three is $2^4$. - Smallest power of 7 is $7^1$. 5. **Calculate HCF:** $$\text{HCF} = 2^4 \times 7 = 16 \times 7 = 112$$ 6. **Answer:** The HCF of 112, 224, and 336 is **112**.