1. The problem requires performing modular arithmetic operations for each given expression. 2. Recall that $a \bmod m$ means finding the remainder when $a$ is divided by $m$. 3. a. Calculate $(9 + 15) \bmod 7 = 24 \bmod 7$. Since $7 \times 3 = 21$, remainder is $24 - 21 = 3$. 4. b. Calculate $(5 + 22) \bmod 8 = 27 \bmod 8$. Since $8 \times 3 = 24$, remainder is $27 - 24 = 3$. 5. c. Calculate $(42 + 35) \bmod 3 = 77 \bmod 3$. Since $3 \times 25 = 75$, remainder is $77 - 75 = 2$. 6. d. Calculate $(25 - 10) \bmod 4 = 15 \bmod 4$. Since $4 \times 3 = 12$, remainder is $15 - 12 = 3$. 7. e. Calculate $(60 - 32) \bmod 9 = 28 \bmod 9$. Since $9 \times 3 = 27$, remainder is $28 - 27 = 1$. 8. f. Calculate $(14 \cdot 18) \bmod 5 = 252 \bmod 5$. Since $5 \times 50 = 250$, remainder is $252 - 250 = 2$. 9. g. Calculate $(9 \cdot 15) \bmod 8 = 135 \bmod 8$. Since $8 \times 16 = 128$, remainder is $135 - 128 = 7$. 10. h. Calculate $(26 \cdot 11) \bmod 15 = 286 \bmod 15$. Since $15 \times 19 = 285$, remainder is $286 - 285 = 1$. 11. i. Calculate $(4 \cdot 22) \bmod 3 = 88 \bmod 3$. Since $3 \times 29 = 87$, remainder is $88 - 87 = 1$. 12. j. Calculate $(5 \cdot 12) \bmod 4 = 60 \bmod 4$. Since $4 \times 15 = 60$, remainder is $0$. Final answers: a. 3 b. 3 c. 2 d. 3 e. 1 f. 2 g. 7 h. 1 i. 1 j. 0