Pressure Gauges Bourdon
1. Problem Statement:
(i) Describe the working principle of pressure gauges with a diagram.
(ii) Calculate the deflection of a Bourdon tube given $r=50$ mm, $E=210$ GPa, $t=0.5$ mm, and pressure $p=200$ kPa.
(iii) Describe an experiment to investigate the photoelectric effect as an example of a radiation transducer.
2. Working Principle of Pressure Gauges:
Pressure gauges measure fluid pressure by converting pressure into mechanical displacement.
A common type is the Bourdon tube gauge, which uses a curved tube that tends to straighten when internal pressure increases.
This mechanical movement is linked to a pointer indicating pressure on a dial.
3. Bourdon Tube Deflection Calculation:
The deflection $\\delta$ of a Bourdon tube under pressure $p$ is given by:
$$\\delta = \\frac{3 p r^2}{E t}$$
where:
- $p$ = internal pressure
- $r$ = initial radius of curvature
- $E$ = Young's modulus
- $t$ = tube thickness
Given:
$p = 200$ kPa = $200 \\times 10^3$ Pa
$r = 50$ mm = 0.05 m
$E = 210$ GPa = $210 \\times 10^9$ Pa
$t = 0.5$ mm = 0.0005 m
Calculate:
$$\\delta = \\frac{3 \\times 200 \\times 10^3 \\times (0.05)^2}{210 \\times 10^9 \\times 0.0005}$$
$$= \\frac{3 \\times 200 \\times 10^3 \\times 0.0025}{105 \\times 10^6}$$
$$= \\frac{1500}{105 \\times 10^6} = 1.4286 \\times 10^{-5} \, m = 14.29 \, \\mu m$$
4. Photoelectric Effect Experiment:
- Shine monochromatic light of known frequency on a clean metal surface inside a vacuum tube.
- Connect the metal to an adjustable voltage circuit and measure the current of emitted electrons.
- Vary the frequency and intensity of light and record the stopping voltage where current ceases.
- Observe that electrons are emitted only above a threshold frequency, confirming the quantum nature of light.
- This experiment demonstrates conversion of radiation energy into electrical energy, characteristic of a radiation transducer.
Final answers:
- Deflection of Bourdon tube: $14.29 \, \\mu m$