1. The problem is to find the uncertainty (±) in the volume measurement given as 4.6 cm³. 2. The uncertainty is often taken as half the smallest division or half the range of the measurement. 3. Here, the range is 4.6 cm³, so the uncertainty is calculated as: $$\text{Uncertainty} = \frac{4.6}{2} = 2.3 \text{ cm}^3$$ 4. Therefore, the volume with uncertainty is expressed as: $$4.6 \pm 2.3 \text{ cm}^3$$ This means the actual volume could be between 2.3 cm³ and 6.9 cm³. 5. This method assumes the uncertainty is symmetric and based on half the range value, which is common in measurement uncertainty estimation.