Acer Practice
1. Problem: Identify which number from the list lies between $-\frac{3}{16}$ and $\frac{5}{64}$.\n\nFirst, approximate the values: $-\frac{3}{16} = -0.1875$ and $\frac{5}{64} = 0.078125$. We check each option:\n- Option A: $-\frac{3}{15} = -0.2$ which is less than $-0.1875$.\n- Option B: $\frac{2}{25} = 0.08$ which is slightly greater than $0.078125$.\n- Option C: $\frac{4}{32} = \frac{1}{8} = 0.125$ which is greater than $0.078125$.\n- Option D: $\frac{6}{80} = \frac{3}{40} = 0.075$ which lies between $-0.1875$ and $0.078125$.\n\nTherefore, option D lies between $-\frac{3}{16}$ and $\frac{5}{64}$.\n\n2. Problem: Calculate the internal volume of an open box made up of five planks each of dimensions $14\text{ cm} \times 15\text{ cm}$ and thickness $0.5\text{ cm}$.\n\nSince the thickness reduces the internal dimensions, subtract twice the thickness from the length and width (assuming height is the plank dimension as well). Thus, the internal length and width are $14 - 2 \times 0.5 = 13$ cm and $15 - 2 \times 0.5 = 14$ cm, but since the box is open, the height equals the full plank dimension $15.5$ cm (sum of plank dimension and thickness). Hence, internal volume = $13 \times 14 \times 15.5$.\n\nTherefore, option A ($13 \times 14 \times 15.5$) gives the internal volume.\n\n3. Problem: Find the formula giving the number of straws in shape $t$ in the pattern.\n\nFrom the pattern: Shape 1 has 4 straws, Shape 2 has 7 straws, Shape 3 has 10 straws, Shape 4 has 13 straws.\n\nThe number of straws increases by 3 in each step, so it fits the form $3t + 1$. Testing:\n- For $t=1$, $3(1) + 1 = 4$\n- For $t=2$, $3(2) + 1 = 7$\n- For $t=3$, $3(3) + 1 = 10$\n\nThus, the rule is $3t + 1$, which is option A.