Thermal Stress
1. **State the problem:** Calculate the increase in stress on steel when the temperature rises from 12°C to 40°C.
2. **Given data:**
- Initial temperature $T_1 = 12^\circ C$
- Final temperature $T_2 = 40^\circ C$
- Coefficient of linear expansion $\alpha = 0.000011$ per $^\circ C$
- Young's modulus $E = 210$ kN/mm²
3. **Formula used:**
The thermal stress $\sigma$ induced due to temperature change when the material is constrained is given by:
$$\sigma = E \alpha \Delta T$$
where $\Delta T = T_2 - T_1$ is the temperature change.
4. **Calculate temperature change:**
$$\Delta T = 40 - 12 = 28^\circ C$$
5. **Calculate increase in stress:**
$$\sigma = 210 \times 0.000011 \times 28$$
$$\sigma = 210 \times 0.000308 = 0.06468 \text{ kN/mm}^2$$
6. **Interpretation:**
The increase in stress on the steel due to the temperature rise is approximately $0.0647$ kN/mm².
This means the steel will experience an additional tensile stress of about $0.0647$ kN/mm² if it is constrained and cannot expand freely.