1. Diberikan fungsi $f(x) = \sqrt{4 - x^2}$. (a) Domain fungsi adalah semua nilai $x$ yang membuat ekspresi di dalam akar tidak negatif, yaitu $4 - x^2 \geq 0$. 2. Menyelesaikan pertidaksamaan: (a) $(x + 4)(2x - 1)^2(x - 3) \leq 0$ (b) $|3x - 4| < 6$ (c) $\frac{x^2 - 2x + 1}{2x^2 - x - 1} \leq 0$ (d) $3|2x - 4| > |x + 2|$ 3. Menghitung limit: (a) $\lim_{x \to 9} \frac{x - 9}{\sqrt{x - 3}}$ (b) $\lim_{x \to \infty} \frac{5x^3 + 7x^2 - 5x}{4x^3 + 16}$ (c) $\lim_{x \to 1} \frac{1 - \sqrt{x}}{1 - x^2}$ 4. Diberikan $f(x) = \frac{4x - 2}{5x + 1}$ dan $g(x) = 3x - 3$. (a) $(f \circ g)(x) = f(g(x)) = f(3x - 3) = \frac{4(3x - 3) - 2}{5(3x - 3) + 1} = \frac{12x - 12 - 2}{15x - 15 + 1} = \frac{12x - 14}{15x - 14}$ (b) $(f \circ g)(\frac{3}{7}) = \frac{12(\frac{3}{7}) - 14}{15(\frac{3}{7}) - 14} = \frac{\frac{36}{7} - 14}{\frac{45}{7} - 14} = \frac{\frac{36 - 98}{7}}{\frac{45 - 98}{7}} = \frac{-\frac{62}{7}}{-\frac{53}{7}} = \frac{62}{53}$ (c) $(f + g)(x) = f(x) + g(x) = \frac{4x - 2}{5x + 1} + (3x - 3)$ (d) $(g \circ f)(x) = g(f(x)) = 3\left(\frac{4x - 2}{5x + 1}\right) - 3 = \frac{3(4x - 2)}{5x + 1} - 3 = \frac{12x - 6}{5x + 1} - 3 = \frac{12x - 6 - 3(5x + 1)}{5x + 1} = \frac{12x - 6 - 15x - 3}{5x + 1} = \frac{-3x - 9}{5x + 1}$ (e) $(g \circ f)(\frac{3}{17}) = \frac{-3(\frac{3}{17}) - 9}{5(\frac{3}{17}) + 1} = \frac{-\frac{9}{17} - 9}{\frac{15}{17} + 1} = \frac{-\frac{9}{17} - \frac{153}{17}}{\frac{15}{17} + \frac{17}{17}} = \frac{-\frac{162}{17}}{\frac{32}{17}} = -\frac{162}{32} = -\frac{81}{16}$ Jawaban lengkap dan penjelasan langkah-langkah tersedia untuk setiap bagian di atas.