1. We need to construct the truth table for the compound proposition $p \oplus p$ where $\oplus$ denotes the exclusive OR (XOR) operation. 2. Recall the XOR truth table: $A \oplus B$ is true if exactly one of $A$ or $B$ is true, but false otherwise. 3. In this case, both inputs to XOR are the same variable $p$, so $p \oplus p$ compares $p$ with itself. 4. Let's list all possible truth values for $p$ and evaluate $p \oplus p$: | $p$ | $p \oplus p$ | |:---:|:------------:| | T | F | | F | F | 5. Explanation: Since both operands are identical, the XOR is false for every input. 6. Final result: $p \oplus p$ is false for all values of $p$ (a contradiction).