1. The problem asks us to write the contrapositive of the statement: "If $x > 3$, then $x^2 > 9$." 2. The original statement is a conditional statement of the form "If P, then Q," where: - P: $x > 3$ - Q: $x^2 > 9$ 3. The contrapositive of a conditional statement "If P, then Q" is "If not Q, then not P." This means we negate both the hypothesis and conclusion and reverse their order. 4. Negating $Q$: The negation of "$x^2 > 9$" is "$x^2 \leq 9$". 5. Negating $P$: The negation of "$x > 3$" is "$x \leq 3$". 6. Therefore, the contrapositive statement is: "If $x^2 \leq 9$, then $x \leq 3$." 7. This contrapositive is logically equivalent to the original statement and is often used in proofs. Final answer: If $x^2 \leq 9$, then $x \leq 3$.