Subjects logic, algebra

Code Cherries 0989Df

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Code Cherries 0989Df


1. **Problem:** Match the codes to the words and find the missing codes for TEND, BAND, TINT, and DENT. 2. **Given:** - BEND = 2 (code 7197) - Codes: (1) 7298, (2) 7197, (3) 6298, (4) 8297, (5) 6498 - Words: BEND, TEND, BAND, TINT, DENT 3. **Step:** Analyze the codes and words. - BEND is matched with code 2 (7197). - Codes likely correspond to words by letter patterns. 4. **Match the rest:** - TEND: Compare with BEND, only first letter changes from B to T. - Code for BEND is 7197, so TEND likely code 1 (7298) or 4 (8297). - BAND and DENT have similar codes 6298 and 6498. - TINT code likely 8297. 5. **Final matching:** - 77 TEND = 1 - 78 BAND = 3 - 79 TINT = 4 - 80 DENT = 5 --- 1. **Problem:** Find who has the most and fewest cherries given: - A + B + C = 96 - A + B = 63 - C + B = 60 2. **Step:** Use equations to find individual amounts. - From A + B + C = 96 - Subtract A + B = 63, get C = 96 - 63 = 33 - From C + B = 60, substitute C = 33, get B = 60 - 33 = 27 - From A + B = 63, substitute B = 27, get A = 63 - 27 = 36 3. **Answer:** - Most cherries: A with 36 - Fewest cherries: B with 27 --- **Summary:** - 77 TEND = 1 - 78 BAND = 3 - 79 TINT = 4 - 80 DENT = 5 - 81 Most cherries: A - 82 Number of cherries: 36 - 83 Fewest cherries: B