1. The problem is to find the matrix $2 \times A$ where $A = \begin{bmatrix} 1 & -1 & 2 \\ 0 & 2 & 1 \\ 0 & 0 & 4 \end{bmatrix}$. 2. To multiply a matrix by a scalar, multiply each element of the matrix by that scalar. 3. Multiply each element of $A$ by 2: $$2 \times A = 2 \times \begin{bmatrix} 1 & -1 & 2 \\ 0 & 2 & 1 \\ 0 & 0 & 4 \end{bmatrix} = \begin{bmatrix} 2 \times 1 & 2 \times (-1) & 2 \times 2 \\ 2 \times 0 & 2 \times 2 & 2 \times 1 \\ 2 \times 0 & 2 \times 0 & 2 \times 4 \end{bmatrix} = \begin{bmatrix} 2 & -2 & 4 \\ 0 & 4 & 2 \\ 0 & 0 & 8 \end{bmatrix}$$ 4. The final answer is: $$2A = \begin{bmatrix} 2 & -2 & 4 \\ 0 & 4 & 2 \\ 0 & 0 & 8 \end{bmatrix}$$