1. The problem is to find the matrix \(A\) given that \(4A = \begin{pmatrix} 4 & -8 & 13 \\ ... & ... & ... \\ ... & ... & ... \end{pmatrix}\).\n\n2. To find \(A\), we divide each element of the matrix \(4A\) by 4 because \(4A\) is the scalar multiplication of matrix \(A\) by 4.\n\n3. For the first element, \(\frac{4}{4} = 1\).\nFor the second element, \(\frac{-8}{4} = -2\).\nFor the third element, \(\frac{13}{4} = \frac{13}{4}\).\n\nHence, the first row of matrix \(A\) is \(\begin{pmatrix} 1 & -2 & \frac{13}{4} \end{pmatrix}\).\n\nSince the rest of the matrix is not provided, we cannot determine the remaining elements of \(A\).\n\nFinal answer: \n$$A = \begin{pmatrix} 1 & -2 & \frac{13}{4} \\ ? & ? & ? \\ ? & ? & ? \end{pmatrix}$$