1. The problem asks about the implication on a connected graph if the number of vertices with odd degree is 1. 2. According to graph theory, specifically Eulerian path and circuit properties: - An Euler Circuit exists if and only if every vertex has an even degree. - An Euler Path (but not a circuit) exists if exactly two vertices have odd degree. - If there are more than two vertices with odd degree, no Euler Path or Circuit exists. 3. Important rule: The number of vertices with odd degree in any graph is always even (this is a fundamental property of graphs). 4. Since the problem states there is exactly 1 odd vertex, this contradicts the rule that the number of odd degree vertices must be even. 5. Therefore, having exactly 1 odd vertex is impossible in a connected graph. 6. Hence, the correct implication is that such a graph cannot exist or be drawn with exactly one odd vertex. Final answer: a. It is impossible to be drawn