Creep Strain Rate
1. **Problem Statement:**
Given the flow law for creep strain rate $$\dot{\varepsilon} = A \sigma_d^n \exp\left(-\frac{Q}{RT}\right)$$ and the frictional strength law $$\tau = c + \mu \sigma_n,$$ we want to understand how to calculate the strain rate $$\dot{\varepsilon}$$ for a given material under stress conditions, using the parameters $A$, $n$, and $Q$ from the provided table.
2. **Formula Explanation:**
- $$\dot{\varepsilon}$$ is the strain rate (s$^{-1}$).
- $A$ is a material constant with units GPa$^{-n}$ s$^{-1}$.
- $\sigma_d$ is the differential stress (GPa).
- $n$ is the stress exponent (dimensionless).
- $Q$ is the activation energy (kJ mol$^{-1}$).
- $R$ is the gas constant, approximately 8.314 J mol$^{-1}$ K$^{-1}$.
- $T$ is the absolute temperature in Kelvin.
3. **Important Notes:**
- Activation energy $Q$ must be converted to J mol$^{-1}$ by multiplying by 1000.
- Temperature $T$ must be in Kelvin.
- Stress $\sigma_d$ must be in GPa to match units of $A$.
4. **Step-by-step Calculation Example:**
Suppose we want to calculate $$\dot{\varepsilon}$$ for dry granite at $\sigma_d = 0.1$ GPa and $T = 600$ K.
- From the table for granite: $$A = 5.0 \times 10^{-3}$$ GPa$^{-n}$ s$^{-1}$, $$n = 3.2,$$ $$Q = 123$$ kJ mol$^{-1}$.
- Convert $Q$ to J mol$^{-1}$:
$$Q = 123 \times 1000 = 123000 \text{ J mol}^{-1}$$
- Calculate the exponential term:
$$\exp\left(-\frac{Q}{RT}\right) = \exp\left(-\frac{123000}{8.314 \times 600}\right) = \exp(-24.65) \approx 1.95 \times 10^{-11}$$
- Calculate $$\sigma_d^n$$:
$$0.1^{3.2} = 10^{-3.2} = 6.31 \times 10^{-4}$$
- Calculate $$\dot{\varepsilon}$$:
$$\dot{\varepsilon} = 5.0 \times 10^{-3} \times 6.31 \times 10^{-4} \times 1.95 \times 10^{-11} = 6.16 \times 10^{-17} \text{ s}^{-1}$$
5. **Interpretation:**
This very low strain rate indicates that at 600 K and 0.1 GPa differential stress, dry granite deforms extremely slowly by creep.
6. **Summary:**
To find strain rate for any material:
- Use the given $A$, $n$, and $Q$.
- Convert $Q$ to J mol$^{-1}$.
- Calculate the exponential term with temperature $T$ in Kelvin.
- Raise differential stress $\sigma_d$ to power $n$.
- Multiply all terms to get $$\dot{\varepsilon}$$.
This method applies to all materials in the table.