1. **State the problem:** We need to find the difference in volumes between a cylindrical block and a rectangular block of wood. 2. **Calculate the volume of the cylindrical block:** - Diameter = 14 cm, so radius $r = \frac{14}{2} = 7$ cm. - Height $h = 10$ cm. - Volume of cylinder $V_{cyl} = \pi r^2 h = \frac{22}{7} \times 7^2 \times 10$. - Simplify: $V_{cyl} = \frac{22}{7} \times 49 \times 10 = 22 \times 7 \times 10 = 1540$ cm$^3$. 3. **Calculate the volume of the rectangular block:** - Dimensions: 15 cm by 10 cm by 5 cm. - Volume $V_{rect} = 15 \times 10 \times 5 = 750$ cm$^3$. 4. **Find the difference in volumes:** - Difference $= V_{cyl} - V_{rect} = 1540 - 750 = 790$ cm$^3$. 5. **Conclusion:** The difference in volumes is 790 cm$^3$. **Answer:** Option c. 790 cm$^3$