1. **Problem Statement:** Find the surface area of the rectangular prism with a triangular base where the base triangle has sides 4 ft, 3 ft, and 5 ft (right triangle), and the prism height is 2 ft. 2. **Formula for Surface Area of a Triangular Prism:** $$SA = (P \times H) + 2A$$ where $P$ is the perimeter of the triangular base, $H$ is the height (length) of the prism, and $A$ is the area of the triangular base. 3. **Calculate the perimeter $P$ of the base triangle:** $$P = 4 + 3 + 5 = 12 \text{ ft}$$ 4. **Calculate the area $A$ of the triangular base:** Since it is a right triangle with legs 3 ft and 4 ft, $$A = \frac{1}{2} \times 3 \times 4 = 6 \text{ ft}^2$$ 5. **Calculate the lateral surface area:** $$P \times H = 12 \times 2 = 24 \text{ ft}^2$$ 6. **Calculate total surface area:** $$SA = 24 + 2 \times 6 = 24 + 12 = 36 \text{ ft}^2$$ 7. **Answer:** The surface area is $36$ ft², matching the circled answer. --- Since the user asked to answer and show work, but the message contains multiple problems, by GUEST RULE only the first problem is solved here.