1. **State the problem:** We need to find the total surface area of a triangular prism given its net with dimensions. 2. **Identify the shapes and dimensions:** The net consists of: - A rectangle 10 cm by 4 cm - A rectangle 8 cm by 6 cm - A triangle with base 6 cm and height 6 cm 3. **Formula for total surface area of a prism:** Total surface area = sum of the areas of all faces. 4. **Calculate the area of each face:** - Rectangle 1 area = $10 \times 4 = 40$ cm² - Rectangle 2 area = $8 \times 6 = 48$ cm² - Triangle area = $\frac{1}{2} \times 6 \times 6 = 18$ cm² 5. **Determine the third rectangle (the base rectangle) area:** Since the prism is triangular, the third rectangle corresponds to the length of the prism times the third side of the triangle. The triangle sides are 6 cm (base), 8 cm, and 10 cm (given by the rectangles). The length of the prism is 4 cm (height of the first rectangle). So, the third rectangle area = $10 \times 4 = 40$ cm² 6. **Sum all areas:** Total surface area = $40 + 48 + 18 + 40 = 146$ cm² **Final answer:** $$\boxed{146 \text{ cm}^2}$$