1. **Problem Statement:**
We have a right triangle inscribed in a circle. The triangle has sides labeled 10.4, 8.4, and $x$, with a right angle between the sides 8.4 and $x$. We need to find the length of $x$.
2. **Formula Used:**
Since the triangle has a right angle, we can use the Pythagorean theorem:
$$a^2 + b^2 = c^2$$
where $a$ and $b$ are the legs of the right triangle, and $c$ is the hypotenuse.
3. **Identify the sides:**
- The side opposite the right angle (hypotenuse) is 10.4.
- The two legs are 8.4 and $x$.
4. **Apply the Pythagorean theorem:**
$$8.4^2 + x^2 = 10.4^2$$
5. **Calculate squares:**
$$8.4^2 = 70.56$$
$$10.4^2 = 108.16$$
6. **Substitute and solve for $x^2$:**
$$70.56 + x^2 = 108.16$$
$$x^2 = 108.16 - 70.56 = 37.6$$
7. **Find $x$ by taking the square root:**
$$x = \sqrt{37.6} \approx 6.13$$
**Final answer:**
$$x \approx 6.13$$
This means the length of the segment $x$ is approximately 6.13 units.
Triangle Side X
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