1. **State the problem:** We need to find the image of triangle $\triangle KLM$ after reflecting it over the vertical line $x = -5$. 2. **Recall the reflection rule:** When reflecting a point $(x,y)$ over the vertical line $x = a$, the $x$-coordinate of the image is $2a - x$, and the $y$-coordinate remains the same. 3. **Apply the rule to each vertex:** - For $K(-6,-9)$: $x' = 2(-5) - (-6) = -10 + 6 = -4$, so $K' = (-4, -9)$. - For $L(-6,-7)$: $x' = 2(-5) - (-6) = -4$, so $L' = (-4, -7)$. - For $M(-5,-10)$: $x' = 2(-5) - (-5) = -10 + 5 = -5$, so $M' = (-5, -10)$. 4. **Final image coordinates:** $K'(-4, -9)$, $L'(-4, -7)$, $M'(-5, -10)$. This completes the reflection of $\triangle KLM$ over the line $x = -5$.