Triangle Enlargement Prism
1. **Problem statement:**
(a) Enlarge triangle A with scale factor $\frac{1}{3}$ and centre of enlargement $(2,6)$.
(b) Prism X and prism Y are similar.
(i) Complete the sentence: The height of prism Y is [ ] times the height of prism X.
(ii) Given volume of prism Y is 95 cm³, calculate volume of prism X.
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2. **Part (a) Enlargement of triangle A:**
- The centre of enlargement is $(2,6)$.
- Scale factor is $\frac{1}{3}$.
- For each vertex $(x,y)$ of triangle A, the image $(x',y')$ is found by:
$$x' = 2 + \frac{1}{3}(x - 2)$$
$$y' = 6 + \frac{1}{3}(y - 6)$$
- Vertices of triangle A are approximately:
- $A_1 = (6,1)$
- $A_2 = (6,5)$
- $A_3 = (8,1)$
- Calculate new vertices:
- For $A_1$:
$$x' = 2 + \frac{1}{3}(6 - 2) = 2 + \frac{4}{3} = \frac{10}{3} \approx 3.33$$
$$y' = 6 + \frac{1}{3}(1 - 6) = 6 - \frac{5}{3} = \frac{13}{3} \approx 4.33$$
- For $A_2$:
$$x' = 2 + \frac{1}{3}(6 - 2) = 3.33$$
$$y' = 6 + \frac{1}{3}(5 - 6) = 6 - \frac{1}{3} = \frac{17}{3} \approx 5.67$$
- For $A_3$:
$$x' = 2 + \frac{1}{3}(8 - 2) = 2 + 2 = 4$$
$$y' = 6 + \frac{1}{3}(1 - 6) = 4.33$$
- So, the enlarged triangle vertices are approximately:
$$\left(\frac{10}{3}, \frac{13}{3}\right), \left(\frac{10}{3}, \frac{17}{3}\right), (4, \frac{13}{3})$$
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3. **Part (b)(i) Surface area ratio and height ratio:**
- Surface area ratio of prism X to prism Y is $1 : 5$.
- For similar solids, surface area ratio = (linear scale factor)$^2$.
- Let linear scale factor be $k$ from X to Y.
Then:
$$k^2 = 5 \implies k = \sqrt{5}$$
- Height of prism Y is $\sqrt{5}$ times the height of prism X.
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4. **Part (b)(ii) Volume calculation:**
- Volume ratio = (linear scale factor)$^3$.
- Volume of prism Y = 95 cm³.
- Volume of prism X = $V_X$.
- Using ratio:
$$\frac{V_X}{95} = \frac{1}{k^3} = \frac{1}{(\sqrt{5})^3} = \frac{1}{5\sqrt{5}}$$
- Calculate $V_X$:
$$V_X = \frac{95}{5\sqrt{5}} = \frac{19}{\sqrt{5}}$$
- Rationalize denominator:
$$V_X = \frac{19}{\sqrt{5}} \times \frac{\sqrt{5}}{\sqrt{5}} = \frac{19\sqrt{5}}{5} \approx 17.0 \text{ cm}^3$$
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**Final answers:**
- (a) Enlarged triangle vertices: $\left(\frac{10}{3}, \frac{13}{3}\right), \left(\frac{10}{3}, \frac{17}{3}\right), (4, \frac{13}{3})$
- (b)(i) Height of prism Y is $\sqrt{5}$ times height of prism X.
- (b)(ii) Volume of prism X is approximately 17.0 cm³.