1. Problem: Given square ABCD is congruent to square PQRS and side AB = 4 cm, find the length of side QR. Since congruent squares have equal corresponding sides, QR = AB = 4 cm. 2. Problem: Given AE = DB, CB = EF and \( \angle ABC = \angle FED \), determine the congruent triangle. Using the information, \( \triangle ABC \cong \triangle FED \) by criteria of congruency. 3. Problem: Identify which is NOT a criterion for congruency of two triangles. Options are ASA, SAS, AAS, SSS. All of these except for AAS (commonly accepted as valid) are traditional congruency criteria. However, AAS is also valid, so none listed are incorrect. Likely a trick, but the problem implies all are criteria so possibly no answer. 4. Problem: Two figures are congruent if they have exactly the same: Answer: shape and size. 5. Problem: In \( \triangle ABC \) and \( \triangle PQR \) given angles and one side, which congruence holds? Given \( \angle A=40^\circ, \angle C=60^\circ, BC=7\text{ cm} \) and \( \angle P=60^\circ, \angle Q=40^\circ, RP=7\text{ cm} \). By angle correspondence and side length, \( \triangle ABC \cong \triangle QRP \). 6. Problem: In \( \triangle ABC \) and \( \triangle DEF \), \( \angle A=\angle D \) and \( AB = FD \), for SAS congruency, We need \( AC = DE \) to satisfy SAS axiom. Final Answers: 1) 4 cm 2) \( \triangle ABC \cong \triangle FED \) 3) None (all given options are valid criteria) 4) shape and size 5) \( \triangle ABC \cong \triangle QRP \) 6) \( AC = DE \)