1. **Problem 1:** Find the area of a triangle with two sides 29 m and 98 m, and included angle 132°. 2. **Formula:** Area = $\frac{1}{2}ab\sin(C)$ where $a$ and $b$ are sides, $C$ is included angle. 3. **Calculation:** $$\text{Area} = \frac{1}{2} \times 29 \times 98 \times \sin(132^\circ)$$ 4. Calculate $\sin(132^\circ)$: $$\sin(132^\circ) = \sin(180^\circ - 48^\circ) = \sin(48^\circ) \approx 0.7431$$ 5. Substitute: $$\text{Area} = \frac{1}{2} \times 29 \times 98 \times 0.7431 = 14.5 \times 98 \times 0.7431$$ 6. Multiply: $$14.5 \times 98 = 1421$$ $$1421 \times 0.7431 \approx 1055.5$$ 7. **Answer 1:** Area $\approx 1055.5$ square meters. 8. **Problem 2:** Find the unknown side of a triangle with sides 77 m and 33 m, and included angle 132°. 9. **Formula:** Use Law of Cosines: $$c^2 = a^2 + b^2 - 2ab\cos(C)$$ 10. Substitute values: $$c^2 = 77^2 + 33^2 - 2 \times 77 \times 33 \times \cos(132^\circ)$$ 11. Calculate squares: $$77^2 = 5929, \quad 33^2 = 1089$$ 12. Calculate $\cos(132^\circ)$: $$\cos(132^\circ) = \cos(180^\circ - 48^\circ) = -\cos(48^\circ) \approx -0.6691$$ 13. Substitute cosine: $$c^2 = 5929 + 1089 - 2 \times 77 \times 33 \times (-0.6691)$$ 14. Calculate product: $$2 \times 77 \times 33 = 5082$$ 15. Multiply by cosine: $$5082 \times (-0.6691) = -3400.5$$ 16. Substitute: $$c^2 = 5929 + 1089 - (-3400.5) = 5929 + 1089 + 3400.5 = 10418.5$$ 17. Find $c$: $$c = \sqrt{10418.5} \approx 102.07$$ 18. **Answer 2:** Unknown side length $\approx 102.07$ meters.