1. **State the problem:** We need to find the total area of a figure composed of a triangle and a parallelogram. 2. **Identify dimensions:** - Triangle base $b_1 = 8$ mm, height $h_1 = 3$ mm. - Parallelogram base $b_2 = 4$ mm, height $h_2 = 5$ mm. 3. **Calculate the area of the triangle:** The area of a triangle is given by $$\text{Area}_{\triangle} = \frac{1}{2} \times b_1 \times h_1 = \frac{1}{2} \times 8 \times 3 = 12 \text{ mm}^2.$$ 4. **Calculate the area of the parallelogram:** The area of a parallelogram is given by $$\text{Area}_{\text{parallelogram}} = b_2 \times h_2 = 4 \times 5 = 20 \text{ mm}^2.$$ 5. **Calculate total area:** Add the areas of the triangle and parallelogram: $$\text{Total Area} = 12 + 20 = 32 \text{ mm}^2.$$ 6. **Conclusion:** The area of the combined figure is **32 square millimeters**.