1. **State the problem:** We need to find the volume of a treasure chest with a cross-section made of a rectangle and a semicircle on top. The rectangle has height 0.6 m and width 0.8 m, and the length of the chest is 1.8 m. 2. **Calculate the area of the rectangular part:** $$\text{Area}_{\text{rectangle}} = \text{height} \times \text{width} = 0.6 \times 0.8 = 0.48 \text{ m}^2$$ 3. **Calculate the radius of the semicircle:** The semicircle sits on top of the rectangle along the width 0.8 m. $$r = \frac{0.8}{2} = 0.4 \text{ m}$$ 4. **Calculate the area of the semicircle:** $$\text{Area}_{\text{semicircle}} = \frac{1}{2} \pi r^2 = \frac{1}{2} \pi (0.4)^2 = \frac{1}{2} \pi \times 0.16 = 0.08\pi \approx 0.2513 \text{ m}^2$$ 5. **Find the total cross-sectional area:** $$\text{Area}_{\text{total}} = 0.48 + 0.2513 = 0.7313 \text{ m}^2$$ 6. **Calculate the volume by multiplying the cross-sectional area by the length:** $$\text{Volume} = 0.7313 \times 1.8 = 1.31634 \text{ m}^3$$ 7. **Round the answer to 2 decimal places:** $$\boxed{1.32 \text{ m}^3}$$