1. The problem involves analyzing two trapezoids, Figure A and Figure B, positioned on a coordinate grid. 2. We want to find the area of each trapezoid using the trapezoid area formula: $$\text{Area} = \frac{(b_1 + b_2)}{2} \times h$$ where $b_1$ and $b_2$ are the lengths of the two parallel sides (bases), and $h$ is the height (the perpendicular distance between the bases). 3. For Figure A: - The trapezoid extends from $x=13$ to $x=20$, so the height $h = 20 - 13 = 7$. - The vertical positions range from $y=18$ to $y=23$. - The lengths of the parallel sides are the horizontal distances at the top and bottom edges. Assuming the trapezoid is aligned vertically, the bases are the lengths along the $y$-axis: - Bottom base $b_1 = 23 - 18 = 5$ - Top base $b_2 = 23 - 18 = 5$ (since the trapezoid is vertical, both bases are equal here, making it a rectangle) - Area of Figure A: $$\text{Area}_A = \frac{(5 + 5)}{2} \times 7 = \frac{10}{2} \times 7 = 5 \times 7 = 35$$ 4. For Figure B: - The trapezoid extends from $x=7$ to $x=13$, so the height $h = 13 - 7 = 6$. - The vertical positions range from $y=14$ to $y=17$. - The lengths of the parallel sides (bases) are: - Bottom base $b_1 = 17 - 14 = 3$ - Top base $b_2 = 17 - 14 = 3$ (again, equal bases, so a rectangle) - Area of Figure B: $$\text{Area}_B = \frac{(3 + 3)}{2} \times 6 = \frac{6}{2} \times 6 = 3 \times 6 = 18$$ 5. Summary: - Area of Figure A is 35 square units. - Area of Figure B is 18 square units. These calculations assume the trapezoids are oriented vertically with parallel sides along the $y$-axis and height along the $x$-axis based on the given coordinates.