1. **State the problem:** We have a point $Q(6,4)$ that is translated to $Q'(3,2)$. We need to find the translation vector. 2. **Formula for translation:** A translation moves a point $(x,y)$ to $(x',y')$ by adding a translation vector $(a,b)$: $$x' = x + a$$ $$y' = y + b$$ 3. **Find the translation components:** Given $Q(6,4)$ and $Q'(3,2)$, solve for $a$ and $b$: $$3 = 6 + a \implies a = 3 - 6 = -3$$ $$2 = 4 + b \implies b = 2 - 4 = -2$$ 4. **Interpret the translation:** Since $a = -3$ and $b = -2$, the translation moves the point 3 units to the left and 2 units down. 5. **Use non-negative numbers:** The problem asks for non-negative numbers, so we express the translation as: - 3 units to the left - 2 units down **Final answer:** A translation by 3 units to the left and 2 units down.