1. **State the problem:** We need to find the area of a training field formed by a rectangle and two semicircles attached to the shorter sides of the rectangle. 2. **Identify given values:** - Rectangle length $= 84$ m - Rectangle width $= 50$ m - Radius of each semicircle $= \frac{50}{2} = 25$ m (since semicircles are on the width sides) 3. **Formula for area:** - Area of rectangle $= \text{length} \times \text{width} = 84 \times 50$ - Area of a circle $= \pi r^2$ - Area of two semicircles $= \text{area of one circle} = \pi r^2$ 4. **Calculate areas:** - Rectangle area $= 84 \times 50 = 4200$ m$^2$ - Circle area $= 3.14 \times 25^2 = 3.14 \times 625 = 1962.5$ m$^2$ 5. **Total area:** $$\text{Total area} = \text{rectangle area} + \text{area of two semicircles} = 4200 + 1962.5 = 6162.5 \text{ m}^2$$ 6. **Answer:** The area of the training field is $6162.5$ square meters.