1. The problem asks us to find the total surface area of a cylindrical candle with radius $r = 14$ cm and height $h = 16$ cm. 2. Recall that the total surface area $A$ of a cylinder is given by: $$A = 2\pi r^2 + 2\pi rh$$ where: - $2\pi r^2$ is the area of the two circular bases, - $2\pi rh$ is the lateral surface area. 3. Substitute the given values into the formula: $$A = 2\pi (14)^2 + 2\pi (14)(16)$$ 4. Calculate each part: $$2\pi (14)^2 = 2\pi (196) = 392\pi$$ $$2\pi (14)(16) = 448\pi$$ 5. Add the two areas: $$A = 392\pi + 448\pi = 840\pi$$ 6. To get a numerical value, approximate $\pi \approx 3.1416$: $$A \approx 840 \times 3.1416 = 2638.94$$ 7. Therefore, the total surface area of the candle is approximately $2638.94$ cm$^2$. Answer: (b) 2638.94 cm²