1. **Surface Area of a Cone**: Given height $h=16$ ft and base diameter $d=12$ ft, so radius $r=\frac{12}{2}=6$ ft. Calculate the slant height $l$ using Pythagoras theorem: $$l=\sqrt{h^2 + r^2}=\sqrt{16^2 + 6^2}=\sqrt{256 + 36}=\sqrt{292} \approx 17.09 \text{ ft}.$$ Surface area of cone = $$\pi r^2 + \pi r l = 3.14 \times 6^2 + 3.14 \times 6 \times 17.09 = 3.14 \times 36 + 3.14 \times 102.54 = 113.04 + 321.86 = 434.9 \text{ ft}^2.$$ 2. **Surface Area of Triangular Prism**: Triangle sides are 15 yd, 17 yd, and 10 yd, length $L=20$ yd. Calculate the semi-perimeter $$s = \frac{15 + 17 + 10}{2} = 21 \text{ yd}.$$ Area of triangle (Heron's formula): $$\sqrt{s(s-15)(s-17)(s-10)} = \sqrt{21(6)(4)(11)} = \sqrt{5544} \approx 74.45 \text{ yd}^2.$$ Surface area = 2 × base area + perimeter of base × length Perimeter of base = 15+17+10 = 42 yd Surface area = $$2 \times 74.45 + 42 \times 20 = 148.9 + 840 = 988.9 \text{ yd}^2.$$ 3. **Surface Area of Circle**: Diameter = 14 in, radius = 7 in. Area = $$\pi r^2 = 3.14 \times 7^2 = 3.14 \times 49 = 153.86 \text{ in}^2.$$ 4. **Surface Area of Cylinder**: Height $h=11$ yd, diameter $d=10$ yd, radius $r=5$ yd. Surface area = $$2\pi r^2 + 2\pi r h = 2 \times 3.14 \times 5^2 + 2 \times 3.14 \times 5 \times 11 = 157 + 345.4 = 502.4 \text{ yd}^2.$$ 5. **Surface Area of Rectangular Prism**: Dimensions $5\times3\times10$ in. Surface area = $$2(lw + lh + wh)=2(5 \times 3 + 5 \times 10 + 3 \times 10)=2(15 + 50 +30)=2 \times 95=190 \text{ in}^2.$$ 6. **Surface Area of Inverted Cone**: Height $h=19$ ft, diameter $d=9$ ft, radius $r=4.5$ ft. Slant height: $$l=\sqrt{19^2 + 4.5^2} = \sqrt{361 + 20.25} = \sqrt{381.25} \approx 19.53 \text{ ft}.$$ Surface area = $$\pi r^2 + \pi r l = 3.14 \times 4.5^2 + 3.14 \times 4.5 \times 19.53 = 63.6 + 276.9 = 340.5 \text{ ft}^2.$$ 7. **Surface Area of Rectangular Prism**: $14\times7\times3$ in Surface area = $$2(14 \times 7 + 14 \times 3 + 7 \times 3) = 2(98 + 42 + 21) = 2 \times 161 = 322 \text{ in}^2.$$ 8. **Surface Area of Hemisphere**: Radius $r=11$ ft. Surface area = $$3\pi r^2 = 3 \times 3.14 \times 11^2 = 3 \times 3.14 \times 121 = 1139.22 \text{ ft}^2.$$ 9. **Surface Area of Triangular Prism** with base sides 2.3 yd, 2.7 yd, 3.4 yd and prism height 1.2 yd. Calculate triangle semi-perimeter $$s=\frac{2.3+2.7+3.4}{2}=4.2 \text{ yd}.$$ Area of triangular base: $$\sqrt{4.2(4.2-2.3)(4.2-2.7)(4.2-3.4)}=\sqrt{4.2 \times 1.9 \times 1.5 \times 0.8} = \sqrt{9.576} \approx 3.1 \text{ yd}^2.$$ Perimeter base = 2.3 + 2.7 + 3.4 = 8.4 yd Surface area = $$2 \times 3.1 + 8.4 \times 1.2 = 6.2 + 10.08 = 16.28 \text{ yd}^2.$$ **Final answers:** 1) 434.9 ft² 2) 988.9 yd² 3) 153.86 in² 4) 502.4 yd² 5) 190 in² 6) 340.5 ft² 7) 322 in² 8) 1139.22 ft² 9) 16.28 yd²