1. The problem asks to draw the net of each figure and calculate its surface area. 2. For figure (a), a triangular pyramid with edges 8 cm, 6 cm, and 6 cm: - We use the formula for the surface area of a triangular pyramid, which is the sum of the areas of its triangular faces. - First, find the area of the base triangle using Heron's formula: $$s = \frac{8 + 6 + 6}{2} = 10$$ $$\text{Area}_{base} = \sqrt{s(s-8)(s-6)(s-6)} = \sqrt{10 \times 2 \times 4 \times 4} = \sqrt{320} = 8\sqrt{5}$$ - The other three faces are triangles formed by the edges meeting at the apex; assuming the pyramid is regular or given no height, we consider the base area only for surface area calculation here. 3. For figure (b), a rectangular prism with dimensions 15 cm (length), 8 cm (width), and 8 cm (height): - The surface area formula is: $$SA = 2(lw + lh + wh)$$ - Substitute values: $$SA = 2(15 \times 8 + 15 \times 8 + 8 \times 8) = 2(120 + 120 + 64) = 2(304) = 608$$ 4. Final answers: - (a) Surface area approximately $$8\sqrt{5} \approx 17.89$$ cm² (base area only, as more info needed for full surface area). - (b) Surface area $$608$$ cm². Note: For (a), full surface area requires height or slant heights of the pyramid, which are not provided.