1. **State the problem:** We have a square divided into 4 horizontal strips (A, B, C, D) of equal height. Each strip is divided into vertical sections: A has 2, B has 3, C has 4, and D has 5. 2. **Given:** If A = 100%, then C = 50%. This means the area of strip C is half the area of strip A. 3. **Calculate areas:** Each strip has equal height, so height = $\frac{1}{4}$ of the square. - Width of A's sections: $\frac{1}{2}$ (2 sections) - Width of B's sections: $\frac{1}{3}$ (3 sections) - Width of C's sections: $\frac{1}{4}$ (4 sections) - Width of D's sections: $\frac{1}{5}$ (5 sections) 4. **Area of each strip:** Area = height $\times$ total width = height $\times$ 1 (since each strip spans full width) Since height is equal for all strips, the total area of each strip is the same: $\frac{1}{4}$. 5. **Area of each vertical section:** - A section area = $\frac{1}{4} \times \frac{1}{2} = \frac{1}{8}$ - B section area = $\frac{1}{4} \times \frac{1}{3} = \frac{1}{12}$ - C section area = $\frac{1}{4} \times \frac{1}{4} = \frac{1}{16}$ - D section area = $\frac{1}{4} \times \frac{1}{5} = \frac{1}{20}$ 6. **Find missing percentages:** - If D = 100%, what is A in %? Area of D strip = $\frac{1}{4}$, area of A strip = $\frac{1}{4}$, so they are equal. Therefore, A = 100% when D = 100%. - If B = 100%, what is D in %? Area of B strip = $\frac{1}{4}$, area of D strip = $\frac{1}{4}$, so they are equal. Therefore, D = 100% when B = 100%. **Final answers:** - If D = 100%, A = 100% - If B = 100%, D = 100%