1. **Stating the problem:** We have a shape composed of an ellipse and two straight parallel lines connecting semicircles at each end. The total length of the shape is 250 meters, and the height (width of the ellipse and straight parts) is 125 meters. We need to calculate the circumference (perimeter) and surface (area) of this figure. 2. **Understanding the shape:** The shape can be seen as a stadium shape (a rectangle with semicircles at each end). The total length is 250 m, and the height is 125 m. 3. **Dimensions:** - Height (width) = 125 m, so the radius of each semicircle is $r = \frac{125}{2} = 62.5$ m. - The total length is 250 m, which includes the two semicircles and the straight part in between. 4. **Length of the straight part:** The straight part length $L$ is total length minus the diameter of the semicircles: $$L = 250 - 2 \times 62.5 = 250 - 125 = 125 \text{ m}$$ 5. **Circumference (perimeter):** The perimeter is the sum of the straight parts and the circumference of the full circle formed by the two semicircles: $$P = 2L + 2\pi r = 2 \times 125 + 2 \pi \times 62.5 = 250 + 125\pi$$ 6. **Surface (area):** The area is the sum of the rectangle area and the area of the full circle formed by the two semicircles: $$A = L \times (2r) + \pi r^2 = 125 \times 125 + \pi \times 62.5^2 = 15625 + \pi \times 3906.25$$ 7. **Final answers:** - Circumference: $$P = 250 + 125\pi \approx 250 + 392.7 = 642.7 \text{ meters}$$ - Surface: $$A = 15625 + 3906.25\pi \approx 15625 + 12261.85 = 27886.85 \text{ square meters}$$