1. **Problem statement:** Find the perimeter of the shape combining a square of side 14 cm and a semicircle of radius 7 cm attached to one side. 2. **Formula:** The perimeter $P$ of this shape is the sum of the square's three sides (since one side is replaced by the semicircle) plus the semicircle's curved edge. 3. **Important rules:** - The perimeter of a square is $4 \times \text{side}$. - The circumference of a full circle is $2\pi r$. - The length of a semicircle is half the circumference: $\pi r$. 4. **Calculate the semicircle perimeter:** $$ \text{Semicircle length} = \pi \times 7 = 3.14 \times 7 = 21.98\text{ cm} $$ 5. **Calculate the square sides contributing to perimeter:** Three sides of the square remain, so: $$ 3 \times 14 = 42\text{ cm} $$ 6. **Sum the parts:** $$ P = 42 + 21.98 = 63.98\text{ cm} $$ 7. **Answer:** The perimeter of the shape is $63.98$ cm.