1. **Problem Statement:** Given a spherical triangle with angles $A=130^\circ$, $B=110^\circ$, and $C=140^\circ$ on a sphere of radius $R=15$ m, determine the spherical excess. 2. **Formula:** The spherical excess $E$ is given by: $$E = (A + B + C) - 180^\circ$$ where $A$, $B$, and $C$ are the angles of the spherical triangle. 3. **Explanation:** - In spherical geometry, the sum of the angles of a triangle is always greater than $180^\circ$. - The amount by which the sum exceeds $180^\circ$ is called the spherical excess. - This excess is related to the area of the spherical triangle but here we only need to find the excess in degrees. 4. **Calculation:** Calculate the sum of the angles: $$130^\circ + 110^\circ + 140^\circ = 380^\circ$$ Calculate the spherical excess: $$E = 380^\circ - 180^\circ = 200^\circ$$ 5. **Answer:** The spherical excess is $200$ degrees.