1. **Problem 13:** Given a triangle with side $p=8$ cm, angle $P=40^\circ$, and angle $Q=65^\circ$, find side $q$ using the Sine Rule. 2. The Sine Rule states: $$\frac{p}{\sin P} = \frac{q}{\sin Q}$$ 3. Substitute the known values: $$\frac{8}{\sin 40^\circ} = \frac{q}{\sin 65^\circ}$$ 4. Solve for $q$: $$q = \frac{8 \sin 65^\circ}{\sin 40^\circ}$$ 5. Comparing with the options, the correct formula is option A: $$q = 8 \frac{\sin 65^\circ}{\sin 40^\circ}$$ --- 6. **Problem 14:** In the cube diagram, find the length of $FH$ given dimensions $24$ cm, $18$ cm, and angle $W^\circ$. 7. $FH$ is the side opposite to angle $30^\circ$ (assuming $W=30^\circ$ from context). 8. Using the sine relation for the right triangle involving $FH$ and the given sides, the length $FH$ equals $$18 \sin 30^\circ$$ 9. Therefore, the correct answer is option C: $$FH = 18 \sin 30^\circ$$