1. The problem states that two triangles are similar, meaning their corresponding sides are proportional. 2. The first triangle has sides 2, 3, and 5. The second triangle has sides $x$, 6, and 10. 3. Since the triangles are similar, the ratios of corresponding sides are equal: $$\frac{x}{2} = \frac{6}{3} = \frac{10}{5}$$ 4. Simplify the known ratios: $$\frac{6}{3} = 2 \quad \text{and} \quad \frac{10}{5} = 2$$ 5. So, the ratio of similarity is 2. Therefore: $$\frac{x}{2} = 2$$ 6. Solve for $x$: $$x = 2 \times 2 = 4$$ 7. The value of $x$ is about 4, which corresponds to option a.