Segment Theorems
1. **State the problem:**
Find the unknown segment lengths $x$ using the appropriate circle theorems.
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### Part I: Determine the theorem to use
1. We have a tangent segment of length 15 and a secant with external segment $x$ and internal segment 14.
**Theorem:** Tangent-Secant Theorem states:
$$\text{tangent}^2 = \text{external secant segment} \times \text{whole secant segment}$$
2. Two secants intersecting inside the circle with segments 9 and $x$ on one, and 16 and 18 on the other.
**Theorem:** Chords/Intersecting Secants Inside Theorem:
$$\text{product of segments on one chord} = \text{product on the other}$$
3. Two secants intersecting outside the circle with external segments 18 and $x$, internal segments 22 and 29 respectively.
**Theorem:** Two Secants Theorem (intersecting outside):
$$\text{external segment} \times \text{whole secant} = \text{external segment} \times \text{whole secant}$$
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### Part II: Solve for $x$ and segment measures
1.
- Set-up (tangent-secant):
$$15^2 = x(x + 14)$$
- Compute:
$$225 = x^2 + 14x$$
- Rearrange:
$$x^2 + 14x - 225 = 0$$
- Solve quadratic:
$$x = \frac{-14 \pm \sqrt{14^2 + 4\times 225}}{2} = \frac{-14 \pm \sqrt{196 + 900}}{2} = \frac{-14 \pm \sqrt{1096}}{2}$$
Since length must be positive,
$$x = \frac{-14 + 33.1}{2} = 9.55$$ (approx)
- Measures:
$$QA = x = 9.55$$
$$AC = QA + 14 = 9.55 + 14 = 23.55$$
$$DB = 15 \ (tangent)$$
2.
- Given secants intersecting inside, so:
$$(9)(x) = (16)(18)$$
- Solve:
$$9x = 288$$
$$x = 32$$
- Measures:
$$EF = x + 9 = 32 + 9 = 41$$ (if $EF$ is whole secant)
$$GE = 16 + 18 = 34$$
(Problem statement incomplete for this part; assuming we only needed $x$.)
3.
- For outside secants:
$$(18)(18+22) = x (x + 29)$$
- Compute:
$$18 \times 40 = x (x + 29)$$
$$720 = x^2 + 29x$$
- Rearrange:
$$x^2 + 29x - 720 = 0$$
- Solve quadratic:
$$x = \frac{-29 \pm \sqrt{29^2 + 4 \times 720}}{2} = \frac{-29 \pm \sqrt{841 + 2880}}{2} = \frac{-29 \pm \sqrt{3721}}{2}$$
$$\sqrt{3721} = 61$$
Choose positive solution:
$$x = \frac{-29 + 61}{2} = 16$$
- Measures:
$$LM = 2x + 3 = 2(16) + 3 = 35$$
$$KM, KU$$ measures depend on specific segments from problem (not fully provided here).