Segment Congruence Midpoint 458Bdb
1. **Problem 3: Determine if JK \cong MN**
Given:
- J(-1, 10), K(-5, 2)
- M(9, -7), N(1, -3)
We need to find the lengths of JK and MN using the distance formula:
$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$
Calculate JK:
$$JK = \sqrt{(-5 - (-1))^2 + (2 - 10)^2} = \sqrt{(-4)^2 + (-8)^2} = \sqrt{16 + 64} = \sqrt{80} = 4\sqrt{5}$$
Calculate MN:
$$MN = \sqrt{(1 - 9)^2 + (-3 - (-7))^2} = \sqrt{(-8)^2 + (4)^2} = \sqrt{64 + 16} = \sqrt{80} = 4\sqrt{5}$$
Since $JK = MN$, the segments are congruent.
2. **Problem 5: Find CE given midpoint D and expressions for CD and DE**
Given:
- D is midpoint of CE
- $CD = 9x - 7$
- $DE = 3x + 17$
Since D is midpoint, $CD = DE$
Set equal and solve for $x$:
$$9x - 7 = 3x + 17$$
Subtract $3x$ from both sides:
$$6x - 7 = 17$$
Add 7 to both sides:
$$6x = 24$$
Divide both sides by 6:
$$x = 4$$
Find $CD$ and $DE$:
$$CD = 9(4) - 7 = 36 - 7 = 29$$
$$DE = 3(4) + 17 = 12 + 17 = 29$$
Total length $CE = CD + DE = 29 + 29 = 58$