Sector Area Perimeter
1. **State the problem:**
We are given two sectors of circles with given radii and central angles. We need to find the perimeter and area of the shaded regions for each sector, taking \(\pi = \frac{22}{7}\).
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### Part (a): Radius \(r=21\) cm (Angle not given explicitly, so we assume the entire sector is a semicircle or find using available info.)
Since angle is not directly provided, we assume it is the full semicircle (180°) or we must find it based on the problem's original diagram if available. Given only radius 21 cm, let's find formulas to use when angle \(\theta\) is given.
The formulas for a sector:
- Arc length \(L = r\theta\) when \(\theta\) is in radians.
- Area \(A = \frac{1}{2}r^{2} \theta\)
- Perimeter \(P = L + 2r\)
If no angle is specified, we cannot find numeric answers. So we proceed to part (c) which has an explicit angle.
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### Part (c): Radius \(r=35\) cm, angle \(\theta=30^\circ\)
2. **Convert angle to radians:**
$$\theta = 30^\circ = \frac{30 \pi}{180} = \frac{\pi}{6}$$
3. **Calculate arc length:**
$$L = r\theta = 35 \times \frac{\pi}{6} = 35 \times \frac{22}{7} \times \frac{1}{6} = 35 \times \frac{22}{42} = 35 \times \frac{11}{21} = \frac{385}{21} = 18.33\text{ cm (approx)}$$
4. **Calculate perimeter of shaded sector:**
$$P = \text{arc length} + 2r = 18.33 + 2 \times 35 = 18.33 + 70 = 88.33 \text{ cm}$$
5. **Calculate area of shaded sector:**
$$A = \frac{1}{2} r^2 \theta = \frac{1}{2} \times 35^2 \times \frac{\pi}{6} = \frac{1}{2} \times 1225 \times \frac{22}{7} \times \frac{1}{6} = 612.5 \times \frac{22}{42} = 612.5 \times \frac{11}{21} = \frac{6737.5}{21} = 320.83 \text{ cm}^2 \text{ (approx)}$$
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**Final answers:**
- **Part (a):** Insufficient information to determine area and perimeter due to missing angle.
- **Part (c):**
- Perimeter \(P \approx 88.33\) cm
- Area \(A \approx 320.83\) cm\(^2\)