1. The problem asks for the degree of rotational symmetry of a regular hexagon. 2. A regular hexagon has 6 equal sides and 6 equal angles. 3. The formula for the degree of rotational symmetry of a regular polygon is $$\frac{360^\circ}{n}$$ where $n$ is the number of sides. 4. For a hexagon, $n=6$, so the degree of rotational symmetry is $$\frac{360^\circ}{6} = 60^\circ$$. 5. This means the hexagon can be rotated by $60^\circ$ increments and still look the same. 6. Therefore, the degree of rotational symmetry for a regular hexagon is $60^\circ$.