1. The problem states that a shape is first rotated clockwise by 45° and then anticlockwise by 90°, resulting in image X. We need to find the original image before these rotations. 2. The net rotation applied to the original image is the sum of the two rotations: clockwise 45° and anticlockwise 90°. Since clockwise is negative and anticlockwise is positive, net rotation = $-45^\circ + 90^\circ = 45^\circ$ anticlockwise. 3. To find the original image from X, we reverse the net rotation. Since X is obtained by rotating the original image anticlockwise by 45°, the original image is obtained by rotating X clockwise by 45°. 4. For each question, we check which option, when rotated clockwise by 45°, matches image X. **Question 45:** - Image X: Circle with diagonal line, arrow bottom-right. - Option (a): Arrow top-left (X rotated clockwise 45° would point top-left). - Option (b): Arrow downwards. - Option (c): Arrow upwards. - Option (d): Arrow downwards. Rotating X clockwise 45° points arrow top-left, matching option (a). **Answer 45:** Option (a). **Question 46:** - Image X: Ellipse with arrow pointing left. - Rotating X clockwise 45° points arrow bottom-left. - Option (a): Arrow top-right. - Option (b): Arrow upwards. - Option (c): Arrow top-left. - Option (d): Arrow bottom-right. None of the options match arrow bottom-left after rotation. **Answer 46:** None of these. **Question 47:** - Image X: Pentagon with downward triangle. - Rotating X clockwise 45° rotates downward triangle to bottom-left. - Option (a): Square with left-facing triangle. - Option (b): Square with upward triangle. - Option (c): Diamond with left-facing triangle. - Option (d): Diamond with upward triangle. Rotating X clockwise 45° matches option (c) diamond with left-facing triangle. **Answer 47:** Option (c).