1. The problem is to translate rhombus CDEF 4 units left and 13 units down on the coordinate plane. 2. The original coordinates are: - C(2,4) - D(6,4) - F(2,8) - E(6,8) 3. Translation 4 units left means subtracting 4 from each x-coordinate. 4. Translation 13 units down means subtracting 13 from each y-coordinate. 5. Calculate the new coordinates: - C': $(2 - 4, 4 - 13) = (-2, -9)$ - D': $(6 - 4, 4 - 13) = (2, -9)$ - F': $(2 - 4, 8 - 13) = (-2, -5)$ - E': $(6 - 4, 8 - 13) = (2, -5)$ 6. The translated rhombus C'D'E'F' has vertices at: - C'(-2, -9) - D'(2, -9) - F'(-2, -5) - E'(2, -5) This completes the translation of the rhombus 4 units left and 13 units down.