1. The problem states we have a rhombus with diagonals intersecting at right angles. 2. The given diagonal lengths are 6 cm and 4 cm, but 3 cm seems ambiguous. We interpret diagonals as 6 cm and 4 cm. 3. The area (surface) of a rhombus is given by $$\text{Area} = \frac{D_1 \times D_2}{2}$$ where $D_1 = 6$ cm and $D_2 = 4$ cm. 4. Calculate area: $$\frac{6 \times 4}{2} = \frac{24}{2} = 12 \text{ cm}^2$$ 5. The perimeter (scope) of a rhombus equals $4 \times$ side length. 6. Side length can be found using half diagonals in right triangle: half diagonal are $\frac{6}{2}=3$ cm and $\frac{4}{2}=2$ cm. 7. Using Pythagoras theorem, side length $s = \sqrt{3^2 + 2^2} = \sqrt{9 + 4} = \sqrt{13} \approx 3.61$ cm. 8. Calculate perimeter: $$4 \times 3.61 \approx 14.44 \text{ cm}$$ Final answer: Surface area = 12 cm² Perimeter = 14.44 cm