1. **State the problem:** We need to find the image of trapezoid PQRS after reflecting it over the line $y = -x$. 2. **Recall the reflection rule:** Reflecting a point $(x,y)$ over the line $y = -x$ transforms it to $(-y,-x)$. 3. **Apply the reflection to each vertex:** - $P(-6,-6) \to P'(-(-6),-(-6)) = (6,6)$ - $Q(-6,2) \to Q'(-2,6) = (-2,6)$ - $R(-4,0) \to R'(0,4) = (0,4)$ - $S(-4,-6) \to S'(6,4) = (6,4)$ 4. **Write the coordinates of the reflected trapezoid:** - $P'(6,6)$ - $Q'(-2,6)$ - $R'(0,4)$ - $S'(6,4)$ 5. **Summary:** The trapezoid PQRS reflected over $y = -x$ has vertices at $P'(6,6)$, $Q'(-2,6)$, $R'(0,4)$, and $S'(6,4)$. This completes the reflection transformation.