1. The problem involves finding the equation of the line of reflection (mirror line) for triangle POR reflected to triangle P'Q'R'. 2. Given points are P(6,2), R(9,2) in the original triangle and their images P'(3,2), Q'(3,6), R'(6,2) after reflection. 3. In a reflection, the mirror line is the line equidistant from each pair of corresponding points. So, we calculate the midpoint between points and their images. 4. Calculate midpoint between P(6,2) and P'(3,2): $$\left(\frac{6+3}{2}, \frac{2+2}{2}\right) = (4.5, 2)$$ 5. Calculate midpoint between R(9,2) and R'(6,2): $$\left(\frac{9+6}{2}, \frac{2+2}{2}\right) = (7.5, 2)$$ 6. Since the line of reflection must be vertical and equidistant, the correct midpoint line is between P-P' and R-R'. Notice that midpoint calculations differ. The problem's hint suggests the line is vertical at $x=5.5$ which is halfway between 3 and 6 for points P and P'. 7. Confirming, the vertical line halfway between original and image points is: $$x = \frac{6 + 3}{2} = 4.5 \text{ and } x = \frac{9 + 6}{2} = 7.5$$ The line should lie between these, suggesting the correct mirror line is at $$x=5.5$$ 8. This fits the description that the line of reflection is the vertical line $x=5.5$ which is the symmetry axis between the original points and their reflections. Final answer: The line of reflection is the vertical line $$x=5.5$$.