1. **State the problem:** We need to find the image of kite STUV after reflecting it over the vertical line $x = -2$. 2. **Recall the reflection rule:** When reflecting a point $(x, y)$ over the vertical line $x = a$, the reflected point $(x', y')$ is given by: $$x' = 2a - x, \quad y' = y$$ 3. **Apply the rule to each vertex:** - For $S(3, -2)$: $$x'_S = 2(-2) - 3 = -4 - 3 = -7, \quad y'_S = -2$$ - For $T(5, 3)$: $$x'_T = 2(-2) - 5 = -4 - 5 = -9, \quad y'_T = 3$$ - For $U(3, 6)$: $$x'_U = 2(-2) - 3 = -7, \quad y'_U = 6$$ - For $V(1, 3)$: $$x'_V = 2(-2) - 1 = -4 - 1 = -5, \quad y'_V = 3$$ 4. **Write the coordinates of the reflected kite STUV':** $$S'(-7, -2), \quad T'(-9, 3), \quad U'(-7, 6), \quad V'(-5, 3)$$ 5. **Summary:** The kite STUV reflected over the line $x = -2$ has vertices at $S'(-7, -2)$, $T'(-9, 3)$, $U'(-7, 6)$, and $V'(-5, 3)$. This completes the reflection transformation.