1. **State the problem:** We need to find the image of rectangle JKLM after reflecting it over the line $y=2$. 2. **Reflection formula:** When reflecting a point $(x,y)$ over the horizontal line $y=k$, the reflected point $(x',y')$ is given by: $$y' = 2k - y$$ The $x$-coordinate remains the same. 3. **Apply the formula to each vertex:** - For $J(-6,-6)$: $y' = 2(2) - (-6) = 4 + 6 = 10$, so $J' = (-6,10)$ - For $K(-2,-6)$: $y' = 4 + 6 = 10$, so $K' = (-2,10)$ - For $L(-2,-4)$: $y' = 4 - (-4) = 4 + 4 = 8$, so $L' = (-2,8)$ - For $M(-6,-4)$: $y' = 4 + 4 = 8$, so $M' = (-6,8)$ 4. **Result:** The reflected rectangle JKLM has vertices $J'(-6,10)$, $K'(-2,10)$, $L'(-2,8)$, and $M'(-6,8)$. This reflection flips the rectangle vertically across the line $y=2$, preserving the $x$-coordinates and adjusting the $y$-coordinates accordingly.