Rectangle Measures
1. The problem states we have a rectangle with length 8 meters and height 5 meters.
2. To find the perimeter of a rectangle, use the formula $$P = 2(\text{length} + \text{width})$$.
3. Substitute the given values: $$P = 2(8 + 5)$$.
4. Simplify inside the parentheses: $$8 + 5 = 13$$.
5. Calculate the perimeter: $$P = 2 \times 13 = 26$$ meters.
6. Since we want the perimeter in centimeters, convert meters to centimeters using $$1\,\text{m} = 100\,\text{cm}$$.
7. Thus, $$26\,\text{m} = 26 \times 100 = 2600\,\text{cm}$$.
8. To find the area of the rectangle, use the formula $$A = \text{length} \times \text{width}$$.
9. Substitute the given values: $$A = 8 \times 5$$.
10. Calculate the area: $$A = 40$$ square meters.
11. Convert square meters to square centimeters using $$1\,\text{m}^2 = 10,000\,\text{cm}^2$$.
12. Thus, $$40\,\text{m}^2 = 40 \times 10,000 = 400,000\,\text{cm}^2$$.
Final answers:
- Perimeter = 2600 cm
- Area = 400000 cm²