Subjects geometry

Rectangle Measures

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Rectangle Measures


1. The problem states we have a rectangle with length 8 meters and height 5 meters. 2. To find the perimeter of a rectangle, use the formula $$P = 2(\text{length} + \text{width})$$. 3. Substitute the given values: $$P = 2(8 + 5)$$. 4. Simplify inside the parentheses: $$8 + 5 = 13$$. 5. Calculate the perimeter: $$P = 2 \times 13 = 26$$ meters. 6. Since we want the perimeter in centimeters, convert meters to centimeters using $$1\,\text{m} = 100\,\text{cm}$$. 7. Thus, $$26\,\text{m} = 26 \times 100 = 2600\,\text{cm}$$. 8. To find the area of the rectangle, use the formula $$A = \text{length} \times \text{width}$$. 9. Substitute the given values: $$A = 8 \times 5$$. 10. Calculate the area: $$A = 40$$ square meters. 11. Convert square meters to square centimeters using $$1\,\text{m}^2 = 10,000\,\text{cm}^2$$. 12. Thus, $$40\,\text{m}^2 = 40 \times 10,000 = 400,000\,\text{cm}^2$$. Final answers: - Perimeter = 2600 cm - Area = 400000 cm²