1. **State the problem:** Ella and Jake built a ramp frame shaped like a rectangular prism with a triangular side. We need to find the total surface area of the ramp, including the bottom, using the net provided. 2. **Identify the shapes and dimensions:** - The ramp has a rectangular base of dimensions $3.5 \text{ m} \times 1.2 \text{ m}$. - The height of the ramp is $0.9 \text{ m}$. - The slant side (hypotenuse of the triangular side) is $1.5 \text{ m}$. - The length of the ramp is $3.5 \text{ m}$. 3. **Calculate the area of each face:** - Bottom rectangle area: $$3.5 \times 1.2 = 4.2 \text{ m}^2$$ - Two triangular sides (right triangles) with base $1.2 \text{ m}$ and height $0.9 \text{ m}$: $$\text{Area of one triangle} = \frac{1}{2} \times 1.2 \times 0.9 = 0.54 \text{ m}^2$$ $$\text{Area of two triangles} = 2 \times 0.54 = 1.08 \text{ m}^2$$ - Rectangular side (vertical side) with dimensions $0.9 \text{ m} \times 3.5 \text{ m}$: $$0.9 \times 3.5 = 3.15 \text{ m}^2$$ - Rectangular slant side with dimensions $1.5 \text{ m} \times 3.5 \text{ m}$: $$1.5 \times 3.5 = 5.25 \text{ m}^2$$ 4. **Add all areas to find total surface area:** $$4.2 + 1.08 + 3.15 + 5.25 = 13.68 \text{ m}^2$$ 5. **Final answer:** The total wood needed to cover the ramp, including the bottom, is exactly **$13.68 \text{ m}^2$**.