1. **State the problem:** Find the volume of a pyramid with a square base where the side length of the base is 11.8 ft and the height is 5.2 ft. 2. **Formula:** The volume $V$ of a pyramid with a square base is given by $$V = \frac{1}{3} \times \text{(area of base)} \times \text{height}$$ Since the base is square, the area of the base is $\text{side}^2$. 3. **Calculate the area of the base:** $$\text{area} = 11.8^2 = 139.24 \text{ ft}^2$$ 4. **Calculate the volume:** $$V = \frac{1}{3} \times 139.24 \times 5.2$$ $$V = \frac{1}{3} \times 723.648 = 241.216$$ 5. **Round the answer:** Rounded to the nearest tenth, $$V \approx 241.2 \text{ ft}^3$$ **Final answer:** The volume of the pyramid is approximately 241.2 cubic feet.